How is the AHfusion used to calculate the energy required to vaporize a
volume of liquid?
O A. Liters liquid x 1000ml/1L x ml/g x g/mol x AHfusion
O B. Liters liquid x 1000ml/1L x g/ml x mol/g < 1/A Hfusion
C. Liters liquid 1000ml/1L x ml/g x g/mol < 1/AHfusion
O D. Liters liquid x 1000ml/1L x g/ml x mol/g < AHfusion

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hope u do well :) ik this maybe hard but you’ll get through it , the answer is D !

Your Question is complete but the options are very much confusing and contradicting. Below you will find the true and full content.

The correct answer for the given question about Enthalpy of vaporisation is ( Volume of liquid in L x 1000 g/L x ΔHvap cal/gm ) where ΔHvap = 540 cal/gm (in case of water).

What is Enthalpy of vaporisation ?

The amount of energy (enthalpy) required to convert a portion of a liquid into a gas is known as the enthalpy of vaporisation, abbreviated as ΔHvap  and also referred to as the latent heat of vaporisation or heat of evaporation.

How to solve this question?

Let E be the energy required to calculate the energy required to vaporise a volume of liquid.

Then,

E = Volume of liquid in L x Density of liquid in gm/L  x ΔHvap in cal/gm

and E will came out in calorie.

E = Volume of liquid in L x 1000 g/L x 540 cal/gm --- (in case of water)

Thus we can conclude that to calculate the energy required to vaporise a volume of liquid, we can use the formula with ΔHvap which is E = (Volume of liquid in L x Density of liquid g/L x ΔHvap cal/gm ) and the answer will be in calorie.

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