Respuesta :

Hrishii

Answer:

[tex] x \approx \: \boxed{49.471}[/tex]

Step-by-step explanation:

[tex] - 5 + 2In(3x) = 5 \\ 2In(3x) = 5 + 5 \\ 2In(3x) = 10 \\ In(3x) = \frac{10}{2} \\ In(3x) = 5 \\ \implies \: 3x = {e}^{5} \\ \implies \: x = \frac{ {e}^{5} }{3} \\ x = \frac{148.41316}{3} \\ x = 49.4710533 \\ x \approx \: \boxed{49.471}[/tex]

Answer:

x= e^ 5 / 3 OR 49.471

Step-by-step explanation:

-5=2In (3x)=5

determine the defined range

-5+2In (3x) = 5, x>0

move the constant to the right- move the five to the right and change the sign

2In (3x)= 5+5

calculate- add them together

2In (3x)=10

divide both sides by 2

In (3x)=5

covert into exponential form ( x=e^5)

3x= e^5

divide both sides by 3

x=e^5/3 , x> 0

(check if the solution is in the defined range) which is the answer

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