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Find the following probabilities based on the standard normal variable Z. (You may find it useful to reference the z table
answers to 4 decimal places.)
a. P(Z > 1.12)
b. P(Z S-2.35)
c. POSZ s 1.34)
d. P(-0.8 sz s 2.44)

Find the following probabilities based on the standard normal variable Z You may find it useful to reference the z table answers to 4 decimal places a PZ gt 112 class=

Respuesta :

mathmate

Answer:

Step-by-step explanation:

a. P(Z > 1.12) = 1-N(1.12) = 1-0.8686431=0.1313569

b. P(Z S-2.35)  => P(Z <= 2.35) = 0.009386706

(please check interpretation of question b)

c. POSZ s 1.34) => P(0 <= Z <= 1.34) =  0.9098773 - 0.5 = 0.4098773

(please check interpretation of question c)

d. P(-0.8 sz s 2.44) => P(-0.8 <= 2.44) = 0.9926564 - 0.2118554 = 0.780801

(please check interpretation of question d)

The probabilities of the standard normal variable are 0.1313, 0.009386, 0.4098773, and 0.780801.

What is a z-score?

The z-score is a numerical measurement used in statistics of the value's relationship to the mean of a group of values, measured in terms of standards from the mean.

The probability of the following standard normal variable will be given by the z-score table.

a. P(z > 1.12) = 1 - P(z = 1.12) = 1 - 0.8686 = 0.1313

b. P(z ≤ -2.35) = P(z < 2.35) = 0.009386

c. P(0 ≤ z ≤ 1.34) = 0.9098773 - 0.5 = 0.4098773

d. P(-0.8 ≤ z s 2.44) = 0.9926564 - 0.2118554 = 0.780801

More about the z-score link is given below.

https://brainly.com/question/13299273

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