9514 1404 393
Answer:
B. 1/2
Step-by-step explanation:
Maybe you want the solution to ...
[tex]9^x-1=2[/tex]
You can use logarithms, or your knowledge of powers of 3 to solve this.
[tex]9^x=3\qquad\text{add 1}\\\\3^{2x}=3^1\qquad\text{express as powers of 3}\\\\2x=1\qquad\text{equate exponents of the same base}\\\\\boxed{x=\dfrac{1}{2}}\qquad\text{divide by 2}[/tex]
Using logarithms, the solution looks like ...
[tex]x\cdot\log{9}=\log{3}\\\\x=\dfrac{\log{3}}{\log{9}}=\dfrac{1}{2}[/tex]
