Answer:
here are two alleles for freckles describes the presence of freckle in one of the sibling.
Explanation:
Freckles are the dominant trait in the human.
There are two alleles for a gene on the homologous chromosome responsible for the trait to be with freckle or no freckles.
In the situation when one child can have and other does not have freckle it shows that parent are heterozygous for the freckle gene.
In heterozygous form one allele will be of dominant and other is of recessive nature.
The cross between the heterozygous parents is shown as:
F f
F FF Ff F is freckle f= no freckle
f Ff ff
From the punnet square it can bee seen that there is 25% chance of no freckle in a sibling when both the parents have freckle.
Other chance is if one of the parent is heterozygous and dominant and the other parent is recessive. From the punnet square
F f
f Ff ff
f Ff ff In this case 50% chance of no freckles in offspring.
So in either case chance of no freckled child is there.
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