Answer: (d) and (e)
Step-by-step explanation:
Given
The function is [tex]y^2=2x+1[/tex]
It can be written as [tex]y=\pm \sqrt{2x+1}[/tex]. So, the domain of the function is
[tex]\Rightarrow 2x+1\geq 0\\\\\Rightarrow x\geq \dfrac{-1}{2}[/tex]
So, for every value of x greater than -0.5. The function has two values of y.
Thus, option (d) and (e) are correct.