Answer: The oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.
Explanation:
Given: [tex]V_{1}[/tex] = 2 L, [tex]P_{1}[/tex] = 2 atm
[tex]V_{2}[/tex] = 1 L, [tex]P_{2}[/tex] = ?
Formula used to calculate the new pressure is as follows.
[tex]P_{1}V_{1} = P_{2}V_{2}[/tex]
Substitute the values into above formula as follows.
[tex]P_{1}V_{1} = P_{2}V_{2}\\2 atm \times 2 L = P_{2} \times 1 L\\P_{2} = 4 atm[/tex]
Thus, we can conclude that the oxygen gas has a pressure of 4 atm if my volume decreases to 1 L.
