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Topic: Modeling exponential functions
Kathy plans to purchase a car that depreciates
(loses value) at a rate of 14% per year. The initial
cost of the car is $21,000. Which equation
represents the value, v, of the car after 3 years?
1) v = 21,000(0.14)
2) v = 21,000(0.86)
3) v= 21,000(1.14)
4) v= 21,000(0.86)(3)

Respuesta :

Luv2Teach

Answer:

Step-by-step explanation:

The standard form equation for this type of problem is

[tex]y=a(b)^x[/tex] where a is the initial value, b is the rate of depreciation, and x is the number of years in question. Because the value of the car is going down, b can also be written as (1 - r) where r is the rate of depreciation. For us, then, the equation will look like this:

[tex]y=a(1-r)^x[/tex] and filling in:

[tex]y=21000(1-.14)^3[/tex] which in simplified form is

[tex]y=21000(.86)^3[/tex] which I'm assuming is how choice 4 should look.

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