Answer: [tex]\dfrac{7}{132}[/tex]
Step-by-step explanation:
Total marbles in the jar = 8+25 = 33
Using combinations, the number of ways of choosing two marbles out of 33= [tex]\dfrac{33!}{2!(33-2)!}\\\\=\dfrac{33!}{2\times31!}\\\\=\dfrac{33\times32}{2}=528[/tex] (total outcomes)
Similarly, the number of ways of choosing two red marbles =
[tex]\dfrac{8!}{2!6!}\\\\=\dfrac{8\times7}{2}=28[/tex](favorable outcomes)
Required probability = [tex]\dfrac{\text{favorable outcomes}}{\text{total outcomes}}[/tex]
[tex]=\dfrac{28}{528}\\\\=\dfrac{7}{132}[/tex]
hence, required probability = [tex]\dfrac{7}{132}[/tex]
