Answer:
[tex]\gamma=0.122^oC[/tex]
Explanation:
From the question we are told that:
Word length[tex]n=14bit[/tex]
Full scale voltage of 100 mV
Thermo-couple shows:
[tex]0.5 mV\ at\ 50^oC[/tex]
[tex]3.052\ mV\ at\ 100^oC.[/tex]
Generally the equation for Average output voltage V_[avg} is mathematically given by
[tex]V_[avg}=\frac{3.052-0.5}{100-50}[/tex]
[tex]V_[avg}=0.05mv[/tex]
Since
[tex]Word lenght =14[/tex]
Therefore
[tex]Voltage\ steps=\frac{100}{2^{14}}[/tex]
[tex]Voltage\ steps=6.10*10^3mv steps[/tex]
Generally the equation for The required temperature resolution\gamma is mathematically given by
[tex]\gamma=\frac{100}{2^{14}*V_[avg}}[/tex]
[tex]\gamma=\frac{100}{2^{14}*0.05}[/tex]
[tex]\gamma=0.122^oC[/tex]
