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Compound EX4 reacts with Y2 giving two products: EX Y and XY. Calculate the E- X bond enthalpy if the reaction liberates 243.6 kJ/mol and other bond enthalpies are:
Y-Y 109 kJ/mol,
X-Y 123.1 kJ/mol and
E-Y 290 kJ/mol.
a. 547.7 kJ/mol
b. 60.5 kJ/mol
c. 234.7 kJ/mol
d. 20.6 kJ/mol
e. 176.9 kJ/mol

Respuesta :

okpalawalter8

Answer:

Option B

Explanation:

From the question we are told that:

Equation

[tex]EX_4+Y_2->EX_3Y+XY[/tex]

Bond enthalpies are:

 [tex]Y-Y 109 kJ/mol,[/tex]

[tex]X-Y 123.1 kJ/mol[/tex]  

[tex]E-Y 290 kJ/mol.[/tex]

Generally the equation for the energy used to break E-X and Y-Y is mathematically given by

 [tex]E_2=109+x[/tex]

Therefore

Total Energy Liberated is

 [tex]E_T=E_1+E_2[/tex]

 [tex]E_T=413.1+109+x[/tex]

 [tex]E_T=304.1-x[/tex]

Since

  [tex]E_T+E_I[/tex]

Therefore

 [tex]304.1-x=243.6[/tex]

 [tex]x=60.5kJ/mol[/tex]

Option B

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