Answer:
[tex]125p^3 + 36^qp^{2q}[/tex]
Explanation:
Identity rules used:
[tex](ab)^x = a^x b^x\\\\(a^{xy}) = (a^x)^y[/tex]
5p raised to 3,
[tex](5p)^3 = 5^3 p^3 = 125p^3[/tex]
6p raised to 2q,
[tex](6p)^{2q} = 6^{2q} \times p^{2q} = (6^2)^q \times p^{2q} = 36^q p^{2q}[/tex]
Final step add them:
[tex]125p^3 + 36^qp^{2q}[/tex]
