Answer:
a) 0.40
b) 0.10
c) 0.60
Step-by-step explanation:
Helena has 80% chance of getting A ,
[tex]P(A_H) = \frac{80}{100} = 0.80[/tex]
Rodriquez has 50% chance of getting A ,
[tex]P(A_R) = \frac{50}{100} = 0.50[/tex]
a)
[tex]P(A_H A_R) = P(A_H) \times P(A_R) = 0.80 \times 0.50 = 0.40[/tex]
b)
[tex]Probability \ Helena \ will \ not \ get \ A\ , \ P(A_H^{'} ) = 1 - P(A_H) = 1 - 0.80 = 0.20[/tex]
Probability Rodriquez will get A and Helena will not
[tex]P(A_RA_H^{'})[/tex] = 0.50 x 0.20 = 0.10
c) Probability neither will obtain A = 1 - Probability both will get A
= 1 - 0.40
= 0.60
