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Let's Solve it!
Given that:
[tex]\quad\quad\quad\quad\tt{E = 6 {c}^{2} - 2c - 1}[/tex]
[tex]\quad\quad\quad\quad\tt{ F = - 4 {c}^{2} + 7c + 5}[/tex]
Formula:
[tex]\quad\quad\quad\quad\tt{E + F = ?}[/tex]
Solution:
[tex]\quad\quad\quad\tt{(6 {c}^{2} - 2c - 1) + ( - 4 {c}^{2} + 7c + 5)}[/tex]
Step by step:
[tex] \quad\quad\quad\quad\tt{ ⟶(6 {c}^{2} ) + ( - 4 {c}^{2}) = \boxed{ \pink{2 {c}^{2} }}}[/tex]
[tex] \quad\quad\quad\quad\tt{ ⟶ ( - 2c) + ( 7c) = \boxed{ \pink{5c }}}[/tex]
[tex] \quad\quad\quad\quad\tt{ ⟶ ( - 1) + ( 5) = \boxed{ \pink{4 }}}[/tex]
Now, it will look like this:
[tex] \quad\quad\quad\quad\tt{E + F =2 {c}^{2} + 5c + 4 }[/tex]
So, E + F is equal to:
[tex] \quad\quad\quad\quad\tt{\boxed{ \boxed{ \color{magenta}{ 2 {c}^{2} + 5c + 4 }}}}[/tex]
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#CarryOnLearning
✍︎ C.Rose❀
