contestada

A 0.277 kg bat is flying 4.25 m/s.
It then doubles its velocity.
How much KE did it gain?

Respuesta :

Answer:

7.51

Explanation:

The mass of the bat is given to us as:

m = 0.277  kg

,

and its initial velocity is:

v

i  = 4.25  m/s

 

When the velocity is doubled, the new value becomes:

v f = 4.25 m/s × 2 = 8.5   m/s

.

The formula for kinetic energy is:

K

=

1

2

m

v

2

.

The change in kinetic energy is:

Δ K = 1 /2( m ) ( v2 f − v 2 i ) = 1 2 ( 0.277)

10-2.5=7.5J

7.51  J

.

The bat gained 7.51 joules.