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[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]
Given,
< BAG = 2x°
< BAC = 90° [ < EAF = 90° (vertically opposite angles are equal to each other)]
< CAD = x°
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Value of x = ?
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From the figure we can see that,
< BAG + < BAC + < CAD = 180° (supplementary angles)
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So to solve,
[tex] < BAG + < BAC + < CAD = 180 \\ 2x + 90 + x = 180 \\ 2x + x + 90 = 180 \\ 3x + 90 = 180 \\ 3x = 180 - 90 \\ 3x = 90 \\ x = \frac{90}{3} \\ x = 30[/tex]
⏩ The value of x is [tex]\boxed{30}[/tex]
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