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Kevin leans a 26-foot ladder against a wall so that it forms an angle of 71^{\circ} ∘ with the ground. How high up the wall does the ladder reach? Round your answer to the nearest hundredth of a foot if necessary.

Respuesta :

Answer:≈24.58

Step-by-step explanation:

The Kevin leans 24.58 feet high up the wall does the ladder reach.

We have given that,

Kevin leans a 26-foot ladder against a wall so that it forms an angle of [tex]71^{\circ}[/tex]ground.

and we have to find the  high up the wall does the ladder reach.

we have to use the trigonometric ratio.

What is the sine ratio?

[tex]sin(\theta)=\frac{opposite}{hypotenuse}[/tex]

So find the height of the wall we have to use the sine ratio suppose the height is x feet

We can see in diagram,

[tex]sin(71)=\frac{x}{26} \\26 sin(71)=x\\x=24.58[/tex]

Therefore,the Kevin leans 24.58 feet high up the wall does the ladder reach.

To learn more about the trigonometric ratio visit:

https://brainly.com/question/24349828

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