Answer:
y = [tex]\frac{3}{2}[/tex]
Step-by-step explanation:
4 = 2² and 8 = 2³ , then
[tex]4^{y}[/tex] = 8, can be written
[tex](2^2)^{y}[/tex] = 2³
[tex]2^{2y}[/tex] = 2³
Since bases on both sides are equal, both 2, then equate exponents
2y = 3 ( divide both sides by 2 )
y = [tex]\frac{3}{2}[/tex]
y = 1.5
Step-by-step explanation:
[tex] {4}^{y} = 8[/tex]
Take the logarithm of both sides and you will get
[tex] \log {4}^{y} = y \log4 = \log8[/tex]
or
[tex]y = \frac{\log8}{ \log4} = 1.5[/tex]
