Perpendicular Definition:
[tex] \large \boxed{m_1m_2 = - 1}[/tex]
Slopes of two different equations multiply each others and must equal to -1. We can also say that the perpendicular occurs only if both equations are negative reciprocal to each others. For example, we are given the equation of y = 2x. The perpendicular to y = 2x would be y = (-1/2)x. See how both are reciprocal to each others.
From the equation below:
[tex] \large{x + 5y = - 2}[/tex]
Since the equation is in the form of Ax+By = C. It is better to use the another slope formula which is:
[tex] \large \boxed{m = - \frac{A}{B} }[/tex]
From the equation above, use the slope formula to find the slope.
[tex] \large{m = - \frac{1}{5} }[/tex]
Therefore the equation has a slope of -1/5. Next to find the perpendicular equation to the original equation. Since our slope is -1/5 - that means the negative reciprocal of -1/5 is 5. Therefore the slope of perpendicular line is 5.
Next we will be using the point-slope form below:
[tex] \large \boxed{y - y_1 = m(x - x_1)}[/tex]
Given the y1 and x1 or (x1,y1) are the points. Our perpendicular slope is 5 which passes through the point (3,0). Substitute both slope and the point in.
[tex] \large{y - 0 = 5(x - 3)}[/tex]
Simplify in the slope-intercept form as we get:
[tex] \large{y = 5x - 15}[/tex]
Answer
Hope this helps and let me know if you have any doubts!
