Answer:
The appropriate solution is "1481.76 N".
Explanation:
According to the question,
Mass,
m = 540 kg
Coefficient of static friction,
[tex]\mu_s[/tex] = 0.28
Now,
The applied force will be:
⇒ [tex]F=\mu_s mg[/tex]
By substituting the values, we get
[tex]=0.28\times 540\times 9.8[/tex]
[tex]=1481.76 \ N[/tex]