Answer: [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
total sides = 6
p (rolling a 1) = [tex]\frac{1}{6}[/tex]
p (rolling a 2) = [tex]\frac{1}{6\\}[/tex]
Note:
or - add
and - multiply
∴ [tex]\frac{1}{6} +\frac{1}{6} = \frac{2}{6}[/tex]
∴ [tex]\frac{2}{6} = \frac{1}{3}[/tex]
hence, p (rolling a 1 or 2) = [tex]\frac{1}{3}[/tex]
