Respuesta :

bhadelsimron19

Answer:

Step-by-step explanation:

[tex]\frac{9-3y}{1-9y} = \frac{8}{5}[/tex]

do cross multiplication

[tex]5(9 - 3y) = 8(1 - 9y)\\45 - 15y = 8 - 72y\\45 - 8 = -72y + 15y\\37 = -57y\\\frac{37}{-57} = y[/tex]

Answer:

[tex]y = - \frac{37}{57} [/tex]

Step-by-step explanation:

[tex] \frac{9 - 3y}{1 - 9y} = \frac{8}{5} [/tex]

[tex] \frac{3(3y - y)}{1 - 9y} = \frac{8}{5} [/tex]

[tex]3(3−y) \times 5=(1−9y) \times 8[/tex]

[tex]45−15y=(1−9y) \times 8[/tex]

[tex]45−15y=8−72y[/tex]

[tex]45+57y=8[/tex]

[tex]57y=8−45[/tex]

[tex]57y=−37[/tex]

[tex]y = - \frac{37}{57} [/tex]

Hope it is helpful....

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