Solve c =(a² + 3b)/4 for b.
Bruv take all my points I literally blow at math :'(
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Answer:
[tex]b=\frac{4c-a^{2} }{3}[/tex]
Step-by-step explanation:
First: multiply both sides by 4. 4 times c is 4c and the other sides cancels out as you are doing the inverse operation of division
Then, you have [tex]4c=a^{2} +3b[/tex]
Subtract both sides by a squared
DO NOT TAKE THE SQUARE ROOT! This is because it is a squared plus 3b so you have to do the inverse of addition
From that you get [tex]4c-a^{2} =3b[/tex]
Finally, divide both sides by 3.
You get [tex]b=\frac{4c-a^{2} }{3}[/tex]