Answer:
[tex](a)\ 200 \to 249 =3[/tex]
[tex](b)\ 150 \to 199 = 0[/tex]
[tex](c)\ Total = 20[/tex]
Step-by-step explanation:
Given
See attachment for cumulative frequency histogram
Solving (a): Swimmers between 200yd and 249yd
To do this, we simply read the data from the 0 mark
From the histogram, we have:
[tex]0 \to 249 = 15[/tex]
and
[tex]0 \to 199 = 12[/tex]
So:
[tex]200 \to 249 = 0 \to 249 - 0 \to 199[/tex]
This gives:
[tex]200 \to 249 = 15-12[/tex]
[tex]200 \to 249 =3[/tex]
Solving (b): Swimmers between 150yd and 199yd
To do this, we simply read the data from the 0 mark
From the histogram, we have:
[tex]0 \to 149 = 12[/tex]
and
[tex]0 \to 199 = 12[/tex]
So:
[tex]150 \to 199 = 0 \to 199 - 0 \to 149[/tex]
This gives:
[tex]150 \to 199 = 12-12[/tex]
[tex]150 \to 199 = 0[/tex]
Solving (c): Total swimmers
To do this, we simply read the longest bar of the histogram
[tex]Longest = 20[/tex]
Hence:
[tex]Total = 20[/tex]
