[tex]\sf\purple{B. \:2(x + 2)(x+1) }[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]
[tex]2 {x}^{2} + 6x + 4[/tex]
Taking 2 as common factor, we have
[tex] = 2 \: ( {x}^{2} + 3x + 2) \\ =2 \: ( {x}^{2} + 2x + x + 2)[/tex]
Taking [tex]x[/tex] as common from first two terms and 1 from last two terms, we have
[tex] = 2 \:[x(x + 2) + 1(x + 2)][/tex]
Taking the factor [tex](x+2)[/tex] as common,
[tex] = 2(x + 2)(x + 1)[/tex]
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
