Please help asap I genuinely cannot figure this out

Find the equation of the parabola that has zeros of x = –2 and x = 3 and a y–intercept of (0,–30).


A) y = 5x2+ 5x – 30

B) y = –5x2 + 5x + 30

C) y = 5x2 – 5x – 30

D) y = x2 – 5x – 30

Respuesta :

Answer:

C

Step-by-step explanation:

We can use the factored form of the quadratic equation, given by:

[tex]y=a(x-p)(x-q)[/tex]

Where a is the leading coefficient and p and q are the zeros.

We have zeros x = -2 and x = 3. So, let p = -2 and q = 3:

[tex]y=a(x+2)(x-3)[/tex]

Next, we are given that our y-intercept is (0, -30).

In other words, when x = 0, y = -30. So:

[tex]-30=a(0+2)(0-3)[/tex]

Solve for a:

[tex]-30=-6a\Rightarrow a=5[/tex]

Hence, our factored equation is:

[tex]\displaystyle y=5(x+2)(x-3)[/tex]

For the standard form, expand:

[tex]y=5(x^2-3x+2x-6)[/tex]

Simplify:

[tex]y=5(x^2-x-6)[/tex]

Distribute:

[tex]y=5x^2-5x-30[/tex]

Our answer is C.

Answer:

5,x6=5

4÷6=6

4=6=8

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