Answer:
Step-by-step explanation:
for side a
take 60 degree as reference angle
using tan rule
tan 60 =opposite /adjacent
[tex]\sqrt{3}[/tex] = a/6
do cross multiplication
6*[tex]\sqrt{3}[/tex] =a*1
[tex]6\sqrt{3} = a[/tex]
for b
using pythagoras theorem
a^2 + b^2 =c^2 (here a nd b are the legs of a right triangle and c is hypotenuse)
6^2 + [tex](6\sqrt{3})^2 = b^2[/tex]
36 + 6*6*3 = b^2
36 + 108 = b^2
144 = b^2
[tex]\sqrt{144}[/tex] = b
14 = b
for angle c
take 45 degree as reference angle
using cos rule
cos 45 = adjacent/hypotenuse
[tex]\frac{1}{\sqrt{2} } = \frac{c}{12}[/tex]
do cross multoplication
[tex]c*\sqrt{2} = 12*1[/tex]
[tex]c = \frac{12}{\sqrt{2} } \\\\c = 6\sqrt{2[/tex]
