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In a particular population, the allele frequency of the ABO blood type alleles are as follows: IA is 20%, IB is 30% and i is 50%. If mating is random and the population is in Hardy-Weinberg equilibrium, what percentage of the population will have type O blood type

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marianaegarciaperedo

Answer:

The genotypic frequency F(ii) = 0.25 = 25%

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

In the blood type cases involving the ABO group, the type of inheritance here is the co-dominance type of inheritance

The percentage of the population with type O blood will be 25%

  • Type A (IA) is dominant to type O (i) and at the same time type B (IB) is also dominant to type O (i).
  • Using the equation - p² + 2pq + q² + 2pr + r² + 2qr = 1
  • Where p² indicates the genotypic frequency with type A (AA) blood and q² indicates genotypic frequency of BB and r² indicates the genotypic frequency of OO.

Since we are finding the percentage with type O blood (r²) where r (allelic frequency of type O) is 0.5 (50%)

r² = 0.5² = 0.25 = 25%.

Learn more about co-dominance: https://brainly.com/question/3578928

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