Answer:
y = - [tex]\frac{1}{5}[/tex] x + 5
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 5x + 2 ← is in slope- intercept form
with slope m = 5
Given a line with slope m then the slope of the line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{5}[/tex]
The line crosses the y- axis at (0, 5 ) ⇒ c = 5
y = - [tex]\frac{1}{5}[/tex] x + 5 ← equation of perpendicular line
Answer:
y = -x/5 + 5
Step-by-step explanation:
Equation of a line L : y=mx+b perpendicular to another line L1 through a point P(p,q)
Given :
L1 : y = 5x+2
P : P(p,q) = P(0,5)
Solution :
Slope of L1 = 5. For L to be perpendicular, product of slopes = -1 =>
m*5=-1, or m = -1/5
Since L passes through P(0,5), using the point slope form of the line L :
L : (y-5) = -(x – 0) / 5
L : y = -x/5 + 5
