What is the final velocity if you have an initial velocity of 4m/s with an acceleration of 2m/s2 over a 5 second interval?

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Explanation:

14 m/ s is the answer. mark me as brainliest

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Answer:

[tex] \large{ \tt{❃ \: EXPLANATION}}: [/tex]

  • We're provided - Initial velocity ( u ) = 4 m/s , acceleration ( a ) = 2 m/s² and time taken ( t ) = 5 second & we're asked to find out the final velocity.

  • Remember : Acceleration is the rate of change of velocity. By definition , we'll use [tex] \tt{a = \frac{v - u}{t} }[/tex] where a = acceleration , v = final velocity , u = initial velocity and t = time taken.

[tex] \large{ \tt{❁ \: LET'S \: START}} : [/tex]

[tex] \large{ \boxed{ \bf{❈ \: a = \frac{v - u}{t}}}} [/tex]

  • Plug the values and then find out the final velocity ( v ) :

[tex] \large{ \tt{⇾ \: 2 = \frac{v - 4}{5}}} [/tex]

  • Apply cross product property

[tex] \large{ \tt{⇾v - 4 = 5 \times 2}}[/tex]

[tex] \large{ \tt{⇾v - 4 = 10}}[/tex]

  • Move 4 to the left hand side and change it's sign

[tex] \large{ \tt{⇾ \: v = 10 + 4}}[/tex]

[tex] \large{ \tt{⇾ \: v = \large{ \boxed{ \tt{14 \: m {s}^{ - 1} }}✔}}}[/tex]

  • And we're done!

[tex] \large{ \boxed{\tt{⟶OUR \: FINAL \: ANSWER : \boxed{ \underline{ \tt14 \: m {s}^{ - 1} }}}}}[/tex]

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[tex] \large{ \ \tt{ \# \: StayInAndExplore \: ☂}}[/tex]

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