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Determine the magnitude of the electrostatic force on a 0.06000 C charged object when it is placed in an electric field of magnitude 1500 N/C

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Answer:

Explanation:

Use the following equation:

[tex]E=\frac{q}{F}[/tex] and solve for F:

[tex]F=\frac{q}{E}[/tex] and filling in:

[tex]F=\frac{.0600}{1500}[/tex]

F = 4.0 × [tex]10^{-4[/tex] N

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