Answer:
The answer is below
Explanation:
The z score is a score used to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:
[tex]z=\frac{p_s-p}{\sigma_p} \\\\Where\ p_s\ is\ the \ sample\ proportion, p\ is\ the\ population\ proportion\ and\\\sigma_p\ is\ the\ standard\ error.\\\\Given\ that\ \sigma_p=0.011\%,p=0.08\%[/tex]
a)
[tex]For\ p_s=0.085\%\\\\z=\frac{0.085-0.08}{0.011} =0.45[/tex]
From the normal distribution table, P(z > 0.45) = 1 - 0.6736 = 32.64%
b) The z score that corresponds to a probability of 95% is 1.65
Therefore:
[tex]1.65=\frac{p_s-0.08}{0.011} \\\\p_s=0.01815+0.08\\\\p_s=0.098\%[/tex]