Answer:
90.71%
Explanation:
From the equation of reaction:
[tex]C_7H_6O_3 + CH_4O --> C_8H_8O_3[/tex]
1 mole of salicylic acid requires 1 mole of methanol in order to produce 1 mole of methyl salicylate.
mole = mass/molar mass
1.6 g of salicylic acid = 1.6/138.121 = 0.012 moles
15 g of methanol = 15/32.04 = 0.47 moles
Salicylic acid is the limiting reagent and hence, 0.012 moles of methyl salicylate would be produced according to the mole ratio above.
0.012 moles of methyl salicylate = 0.012 x 152.1494 = 1.83 g
The theoretical yield of methyl salicylate is 1.83 g while the actual yield is 1.66 g.
Percentage yield = actual yield/theoretical yield x 100%
1.66/1.83 x 100% = 90.71%
