Answer:
t = 9.5 seconds
Step-by-step explanation:
Given that,
The initial velocity of the projectile is 304 ft/s
The height of the projectile is given by :
[tex]H=16t^2 + 304t[/tex]
For maximum height,
Put h' = 0
[tex]h'=-32t+304[/tex]
or
[tex]-32t+304=0\\\\t=\dfrac{304}{32}\\\\t=9.5 \ s[/tex]
So, the time taken to reach the maximum height is 9.5 seconds.