Answer:
1.6875 m
Explanation:
Here, we are given that,
- Initial velocity (u) = 0 (as it starts from rest)
- Acceleration (a) = 1.5 m/s²
- Time taken (t) = 1.5 s
Then,
By using the second equation of motion,
★ s = ut + ½at²
- s is distance
- u is initial velocity
- t is time
- a is acceleration
⇒ s = 0(1.5) + ½ × 1.5 × (1.5)²
⇒ s = ½ × 1.5 × 2.25
⇒ s = ½ × 1.5 × 2.25
⇒ s = ½ × 3.375
⇒ s = 1.6875 m
∴ Distance travelled by it is 1.6875 m.
