Factor by Grouping:
15xy + 35x – 12y – 28
O (3y - 7)(5x + 4)
O (3xy + 7)(5x + 4)
O (3xy - 7)(5x - 4)
O (5x - 4)(3y + 7)

Respuesta :

Answer:

[tex](5x - 4)(3y + 7)[/tex]

Step-by-step explanation:

[tex]15xy+35x−12y−28[/tex]

[tex](15xy+35x)−12y−28[/tex]

[tex]5x(3y+7)−4(3y+7)[/tex]

[tex](5x - 4)(3y + 7)[/tex]

Hope it is helpful...

[tex]\longrightarrow{\green{d.\:(5x - 4)(3y + 7)}}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex]15xy + 35x - 12y - 28[/tex]

Taking "[tex]5x[/tex]" as common from first two terms and "[tex]4[/tex]" from last two terms, we have

[tex] = 5x(3y + 7) - 4(3y + 7)[/tex]

Taking the factor [tex](3y+7)[/tex] as common,

[tex] = (5x - 4)(3y + 7)[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}[/tex]