Given:
JH = 3.2 feet
IJ = 5 feet
∠J = 90°
To find:
Angle of I to the nearest tenth
Steps:
In this triangle we know, base length and height but we don't know the hypotenuse of the triangle. So we will use tangent as it only requires height and base length
Tan x = [tex]\frac{opposite}{adjacent}[/tex]
Tan x = [tex]\frac{JH}{IJ}[/tex]
Tan x = [tex]\frac{3.2}{5}[/tex]
Tan x = 0.64
x = [tex]Tan^{-1} (0.64)[/tex]
Now using the natural tangent table or arctan calculator, we find
x = 32.6°
Therefore, the measure of angle I is 32.6°.
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