A small school with 60 total students records how many of their students attend school on each of the 180
days in a school year. The mean number of students in attendance daily is 55 students and the standard
deviation is 4 students. Suppose that we take random samples of 5 school days and calculate the mean
number of students ĉ in attendance on those days in each sample.
Calculate the mean and standard deviation of the sampling distribution of

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Answer:

The answer is below

Explanation:

Given that the mean of the attendance of the population (μ) = 55 students, and the standard deviation (σ) = 55 students

If repeated random samples of a given size n are taken from a population with a population mean of μ and the population standard deviation of σ,  then the mean of the sample distribution ([tex]\mu_x[/tex]) is population mean μ, while the standard deviation of the sample distribution ([tex]\sigma_x[/tex]) is the population standard deviation divided by the square root of the sample size.

Given a random sample (n) of 5 days, hence:

mean of sampling distribution ([tex]\mu_x[/tex]) = μ = 55 students

standard deviation of the sampling distribution = [tex]\sigma_x[/tex] = [tex]\frac{\sigma}{\sqrt{n} }=\frac{4}{\sqrt{5} } =1.79[/tex]