The steps required to solve the given equation is required.
First step: Identify a = 1, b = 3 and c = -4
Second step: [tex]x=\dfrac{-3\pm \sqrt{3^2-4\times 1\left(-4\right)}}{2\times1}[/tex]
Last step: x = 1 and x = -4
Quadratic equation
The given equation is
[tex]x^2+3x-4=0[/tex]
Comparing with the general quadratic equation [tex]ax^2+bx+c=0[/tex] we have
a = 1
b = 3
c = -4
Applying the formula
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\Rightarrow x=\dfrac{-3\pm \sqrt{3^2-4\times 1\left(-4\right)}}{2\times1}\\\Rightarrow x=1\ \text{and}\ -4[/tex]
Learn more about solving quadratic equations:
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