Respuesta :
Answer:
D. 0.33
Step-by-step explanation:
To solve this question, we use Venn probabilities.
I am going to say that:
Event A: Ordered fish of the day.
Event B: Are wearing a tie.
Of 60 diners in a restaurant, 15 ordered the fish of the day
This means that [tex]P(A) = \frac{15}{60}[/tex]
7 are wearing a tie.
This means that [tex]P(B) = \frac{7}{60}[/tex]
Of the diners who ordered fish, 2 are wearing a tie.
This means that [tex]P(A \cap B) = \frac{2}{60}[/tex]
Which is the probability that one of the diners ordered the fish or is wearing a tie?
This is:
[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]
Replacing with the values we have:
[tex]P(A \cup B) = \frac{15}{60} + \frac{7}{60} - \frac{2}{60} = \frac{15 + 7 - 2}{60} = \frac{20}{60} = 0.33[/tex]
The correct answer is given by option d.
