Answer:
[tex]v = 33.95m/s[/tex]
Step-by-step explanation:
Given
[tex]h = 58.8m[/tex] --- height
[tex]u = 0[/tex] --- initial velocity
[tex]g = 9.8m/s^2[/tex] --- acceleration
Required
The velocity when he hit the water
The velocity is then calculated using:
[tex]v^2 = u^2 + 2gh[/tex]
This gives:
[tex]v^2 = 0^2 + 2*9.8 * 58.8[/tex]
[tex]v^2 = 0 + 1152.48[/tex]
[tex]v^2 = 1152.48[/tex]
Solve for v
[tex]v = \sqrt{1152.48[/tex]
[tex]v = 33.95m/s[/tex]
