The co-ordinate of the focus of the given equation of the parabola x^2=6y is (0,3/2).
We have given the equation is
[tex]x^2 = 6y[/tex]
We know that the general equation of the parabola is,
[tex]x^2=4ay[/tex]
A line that passes through the focus and divides the parabola into two halves is known as the axis of symmetry.
What are the coordinates of the focus?
The coordinates of the focus [tex]f(0, a)[/tex]
We have to determine the value of
[tex]a4a=6a \implies 6/4a=3/2[/tex]
Therefore the coordinate of the focus is[tex](0,3/2)[/tex].
To learn more about the focus visit:
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