Respuesta :

msm555

Answer:

Solution given:

[tex] \frac{1 + \sin( \alpha ) }{1 - \sin( \alpha ) } - \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } [/tex]

[tex] \frac{(1 + \sin( \alpha )) {}^{2} - (1 - \sin( \alpha ) {}^{2} }{1 - \sin{}^{2} \alpha }[/tex]

[tex] \frac{1 + 2 \sin( \alpha ) + \sin {}^{2} ( \alpha ) - 1 + 2 \sin( \alpha ) - \sin {}^{2} ( \alpha ) }{ { \cos }^{2} \alpha } [/tex]

[tex] \frac{4 \sin( \alpha ) }{ \cos {}^{2}( \alpha ) } [/tex]

[tex]4 \tan( \alpha ) \sec( \alpha ) [/tex]

is your answer.