Find the approximate value of x (Round to the nearest tenths place)
X
4
12
Pls help
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Answer:
8
Step-by-step explanation:
By intersecting tangent secant theorem:
[tex] {x}^{2} = 4(4 + 12) \\ \\ {x}^{2} = 4 \times 16 \\ \\ {x}^{2} = 64 \\ \\ x = \sqrt{64} \\ \\ x = 8[/tex]
Answer:
6.9
Step-by-step explanation:
If a secant segment and tangent segment are drawn to a circle from the same external point, the product of the length of the secant segment and its external part equals the square of the length of the tangent segment
x² = 4 * 12
x² = 48
Take the square root of both sides
x = 6.9282032303
Rounded
x = 6.9