Answer:
The angle Rick must kick the ball to score is an angle between the lines BX and BZY which is less than or equal to 32°
Step-by-step explanation:
The given measures of the of the angle formed by the tangent to the given circle at X and the secant passing through the circle at Z and Y are;
[tex]m\widehat{XZ} = 58^{\circ}[/tex]
[tex]m\widehat{XY} = 122^{\circ}[/tex]
The direction Rick must kick the ball to score is therefore, between the lines BX and BXY
The angle between the lines BX and BXY = ∠XBZ = ∠XBY
The goal is an angle between [tex]m\widehat{XY}[/tex]
Let 'θ' represent the angle Rick must kick the ball to score
Therefore the angle Rick must kick the ball to score is an angle less than or equal to ∠XBZ = ∠XBY
By the Angle Outside the Circle Theorem, we have;
The angle formed outside the circle = (1/2) × The difference of the arcs intercepted by the tangent and the secant
[tex]\therefore \angle XBZ = \dfrac{1}{2} \times \left (m\widehat{XY} -m\widehat{XZ} \right)[/tex]
We get;
∠XBZ = (1/2) × (122° - 58°) = 32°
The angle Rick must kick the ball to score, θ = ∠XBZ ≤ 32°
