A painter is going to apply a special coating to a triangular metal plate on a new building. Two sides
measure 14.9 cm and 14.7 cm. She knows that the angle between the two sides is 124°. What is the
area of the surface she plans to cover with the coating?

Respuesta :

Answer:

[tex]Area = 90.03cm^2[/tex]

Step-by-step explanation:

Given

[tex]s_1 = 14.9[/tex]

[tex]s_2 = 14.7[/tex]

[tex]\theta = 124[/tex] --- angle in between

Required

The area of the plate

Since [tex]\theta = 124[/tex] is between [tex]s_1[/tex] and [tex]s_2[/tex]

The area is:

[tex]Area = \frac{1}{2} * s_1 * s_2 * \sin(\theta)[/tex]

[tex]Area = \frac{1}{2} * 14.9 * 14.7 * \sin(124.7)[/tex]

[tex]Area = \frac{1}{2} * 14.9 * 14.7 * 0.8221[/tex]

[tex]Area = 90.03cm^2[/tex]