Answer:
[tex]V_2=1344L[/tex]
Explanation:
Hello there!
In this case, since we have a problem about volume-pressure relationship, the idea here is to use the Boyle's law to calculate the final volume as shown below:
[tex]P_2V_2=P_1V_1\\\\V_2=\frac{P_2V_2}{P_1}\\[/tex]
Then, we plug in the initial and final pressures and the initial volume to obtain:
[tex]V_2=\frac{14.00L*0.9600atm}{0.01000atm}\\\\V_2=1344L[/tex]
Regards!