Answer:
[tex]\Delta _{fus}H=205J/g=13.03kJ/mol[/tex]
Explanation:
Hello there!
In this case, since the heat of fusion is a property that allows us to calculate the heat involved during the change from solid to liquid (fusion) and is calculated as shown below:
[tex]Q=m*\Delta _{fus}H[/tex]
In such a way, given the heat involved during this process and the mass of copper, we calculate the heat of fusion as shown below:
[tex]\Delta _{fus}H=\frac{Q}{m}=\frac{41000J}{200.g}\\\\\Delta _{fus}H=205J/g[/tex]
Or in kJ/mol:
[tex]\Delta _{fus}H=205\frac{J}{gCu}*\frac{63.546 gCu}{1molCu}\\\\ \Delta _{fus}H=13026.93J/mol=13.03kJ/mol[/tex]
Regards!
