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How many moles of sodium hydroxide would have to be added to 150 mL of a 0.483 M acetic acid solution, in order to prepare a buffer with a pH of 4.480

Respuesta :

Answer:

0.068 moles of sodium hydroxide would have to be added to 150 mL of a 0.483 M acetic acid solution

Explanation:

As we know  

pH = pKa + log [salt]/[acid]

4.480= 4.74 + log [salt]/[acid]

log [salt]/[]acid] = -0.06

[salt]/[acid] = 0.87

moles acid = 0.150 L x 0.483 mol/L = 0.07245 moles acid

x/0.07245-x = 0.87

X- 0.07245 X = 0.87 *0.07245

X = 0.068 moles

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