contestada

If two proton approach each other with speed of 400m\s and 450m\s respectively what is the total momentum of the two particle system

Respuesta :

Answer: [tex]83.65\times 10^{-27}\ kg.m/s[/tex]

Explanation:

Given

The velocities of the protons are 400 m/s and 450 m/s

Mass of the Proton is [tex]m=1.673\times 10^{-27}\ kg[/tex]

Since they travel in the opposite direction, therefore, their momentum cancels out each other.

Momentum is the product of mass and velocity

[tex]\therefore m(450-400)\\\Rightarrow 1.673\times 10^{-27}\times 50\\\Rightarrow 83.65\times 10^{-27}\ kg.m/s[/tex]

The direction of momentum is in the direction of proton having 450 m/s velocity.